Introduction to easy geometry:
The geometry is one of the major easy parts in math. It is very simple, made easy and understand the concepts to the students. In math, the geometry is deals some of the shapes like triangle, line, circle, sphere etc. In geometry, the shapes contain height, width, and base. We can find the area and volumes by using that shape formulas. I like to share this Plotting a Graph with you all through my article.
Some of the basic shapes are:
Triangle : The triangle is basic shapes of the geometry. It made by three sides with three corners. The line is defined as straight curve.
Circle : The circle is made by the set of points that are a same distance from a point, or center.
Sphere : The sphere is made by set of points in space central from a certain point.
In this article we will solve the some of the geometry example problems.
Examples in geometry:
Example 1:
Calculate the area of a triangle with height 15 cm and base of 5.2 cm.
Solution:
Step 1:
The formula for area of the triangle is `1/2` (bxh)
In this formula the b represented as base, and h is represented as height of the triangle.
Here, the base = 5.2cm, height = 15cm.
As a first step we will substitute the base and height in the formula.
= `1/2` (5.2 x 15)
Step 2:
= `1/2` (78)
= 39
So, the area of the triangle is 39 cm2.
Example 2:
What is the slope of the geometric line which passes through (17, 22) and (23, 28)?
Solution:
Step 1: As a first step we will substitute the values in the formula.
We know that the slope of a given line can be found as m =`(Y2-Y1)/(X2-X1)`
Here, x1 = 17 x2 = 23 y1= 22 y2 =28.
m = `(28-22)/(23-17)`
Step 2:
=` 6/6`
= 1
m =1
So the slope of the line is found to be 1.
Understanding Classifying Triangles is always challenging for me but thanks to all math help websites to help me out.
More Example in Geometry:
Example 3:
The radius of a circle is 8cm^2 inches.
What is area of the circle?
Formula = Π r^2.
= 3.14 `xx` 8 `xx` 8
= 200.96cm^2
Example 4:
What is the volume of the sphere with the radius having 2.5 meter?
Solution:
Step 1:
We know the formula for finding volume of the sphere = `4/3` П r^3
Here П = 3.14, r = 2.5 meter and insert the value into formula we get
Volume = `4/3` x 3.14 (2.5)3
Step 2:
Simplify the above we get
= `4/3` x 3.14 x 2.5 * 2.5 * 2.5
Simplify the above we get
= `4/3` x 49.06
= 65.41m^3
The above example problems are very easy to understand the geometry.
The geometry is one of the major easy parts in math. It is very simple, made easy and understand the concepts to the students. In math, the geometry is deals some of the shapes like triangle, line, circle, sphere etc. In geometry, the shapes contain height, width, and base. We can find the area and volumes by using that shape formulas. I like to share this Plotting a Graph with you all through my article.
Some of the basic shapes are:
Triangle : The triangle is basic shapes of the geometry. It made by three sides with three corners. The line is defined as straight curve.
Circle : The circle is made by the set of points that are a same distance from a point, or center.
Sphere : The sphere is made by set of points in space central from a certain point.
In this article we will solve the some of the geometry example problems.
Examples in geometry:
Example 1:
Calculate the area of a triangle with height 15 cm and base of 5.2 cm.
Solution:
Step 1:
The formula for area of the triangle is `1/2` (bxh)
In this formula the b represented as base, and h is represented as height of the triangle.
Here, the base = 5.2cm, height = 15cm.
As a first step we will substitute the base and height in the formula.
= `1/2` (5.2 x 15)
Step 2:
= `1/2` (78)
= 39
So, the area of the triangle is 39 cm2.
Example 2:
What is the slope of the geometric line which passes through (17, 22) and (23, 28)?
Solution:
Step 1: As a first step we will substitute the values in the formula.
We know that the slope of a given line can be found as m =`(Y2-Y1)/(X2-X1)`
Here, x1 = 17 x2 = 23 y1= 22 y2 =28.
m = `(28-22)/(23-17)`
Step 2:
=` 6/6`
= 1
m =1
So the slope of the line is found to be 1.
Understanding Classifying Triangles is always challenging for me but thanks to all math help websites to help me out.
More Example in Geometry:
Example 3:
The radius of a circle is 8cm^2 inches.
What is area of the circle?
Formula = Π r^2.
= 3.14 `xx` 8 `xx` 8
= 200.96cm^2
Example 4:
What is the volume of the sphere with the radius having 2.5 meter?
Solution:
Step 1:
We know the formula for finding volume of the sphere = `4/3` П r^3
Here П = 3.14, r = 2.5 meter and insert the value into formula we get
Volume = `4/3` x 3.14 (2.5)3
Step 2:
Simplify the above we get
= `4/3` x 3.14 x 2.5 * 2.5 * 2.5
Simplify the above we get
= `4/3` x 49.06
= 65.41m^3
The above example problems are very easy to understand the geometry.
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